Question

I need help with this

help me out if you know the answer.​

Answer 1

The answer is

`$ (3x^2 - 12x + 43) + (-190)/((x+4)) $`

Where

Remainder = -190

quotient =
`3x^2 - 12x + 43`

Explanation:

The dividend is given as

`3x^3 - 5x -18`

The divisor is given as

`x + 4`

Using the long division,

Multiply
`(x + 4)` by
`3x^2`

Remainder:

`-12x^2 - 5x -18`

Multiply
`(x + 4)` by
`-12x`

Remainder:

`43x - 18`

Multiply
`(x + 4)` by
`43`

Remainder:

`-190`

Therefore, the answer is

`$ (3x^2 - 12x + 43) + (-190)/((x+4)) $`

Where

Remainder = -190

quotient =
`3x^2 - 12x + 43`