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2 votes
long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC/m3) distributed throughout its volume. Determine the magnitude of the electric field 15 cm from the axis of the cylinder.

asked
User Helderco
by
7.9k points

1 Answer

3 votes

Answer:

the magnitude of the electric field = 27.1058 V/m

≈ 27 V/m

Step-by-step explanation:

given

R(radius enclosed) = 12 cm = 0.12 m

ρ(charge density) = 5.0 nC/m³ = 5.0 × 10⁻⁹C/m³

r(radius from the axis) = 15 cm = 0.15 m

using Gauss law, which states that the electric flux through any closed surface is directly proportional to the total electric charge enclosed by this surface.

attached is the calculation of the question, using Gauss law of electrostatics

long nonconducting cylinder (radius = 12 cm) has a charge of uniform density (5.0 nC-example-1
answered
User Limak
by
7.8k points
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