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Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)

Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)
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Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)

Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)-example-1
Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)-example-1
Given: DF and DE are midsegments of ∆ABC Prove: DE= 1/2 AC (PLEASE HELP)-example-2
asked
User Jianweichuah
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2 Answers

4 votes

Answer:

The correct answer is D because we proved that the triangles ΔDBE and ΔADF are congruent so that means that DE = segment A F because of CPCTC.

Explanation:

answered
User Matcygan
by
7.9k points
2 votes

Answer:

The correct answer is D because we proved that the triangles ΔDBE and ΔADF are congruent so that means that DE = segment A F because of CPCTC.

answered
User Vaughany
by
8.9k points
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