Question

A jar contains only pennies, nickels, and dimes. The number of dimes is one more than the number of nickles, and the number of pennies is six more than the number of nickels. How many of each denomination are in the jar, if the total value is $4.80?

Answer 1

Nickels=29

Dime=30

Pennies=35

Explanation:

Nickels=$0.05

Dime=$0.10

Pennies=$0.01

Total value=$4.80

Let quantity of

Pennies=p

Nickels=n

Dimes=d

d=n+1

p=n+6

0.01 *[n + 6] + 0.05n + 0.10*[n+1] =4.80

Open parenthesis

0.01n+0.06+0.05n+0.10n+0.10=4.80

0.16n+0.16=4.80

0.16n=4.80-016

0.16n=4.64

n=29

Pennies=n+6

=29+6

=35

Dime=n+1

=29+1

=30