Question

Determine the minimum gauge pressure needed in the water pipe leading into a building if water is to come out of a faucet on the fourteenth floor, 43

Answer 1

The gauge pressure is
`P = 4.2*10^(5) \ N/m^2`

Step-by-step explanation:

From the question we are told that

The height of the 14th floor from the point where the water entered the building is h = 43 m

The gauge pressure is mathematically represented as

`P = mgh`

Where the m is the mass of the water which is mathematically represented as

`m = (\rho)/(V)`

Where
`\rho` is the density of the water which has a constant value of
`\rho = 1000 \ kg/m^3` and this standard value of density the volume is
`1 m^3` so

`m = (1000)/(1)`

`m = 1000 \ kg`

Thus

`P = 1000 * 9.8 * 43`

`P = 4.2*10^(5) \ N/m^2`