Question

How do you factorise this using DOPS/DOTS?

2(x + 3)^2-10

Answer 1

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Explanation:

Answer 2

Explanation:

Hello,

`2(x+3)^2-10\\=2[(x+3)^2-5]\\=2[(x+3)^2-(√(5))^2]\\\\=2[(x+3+√(5))(x+3-√(5))]`

Hope this helps