Question

Write the point-slope form of an equation of the line through the points (6, -1) and (5, -7).

A. Y- 6 = 6(x + 1)
B.y - 5 = 6(x + 7)
C.Y+7= 6(x + 5)
D.y +1 = 6:1-6)

Answer 1

D.y + 1 = 6(x - 6)

Explanation:

The general form of a straightline equation is given as

y = mx + c

where m is the slope and c is the intercept

m = Δy/Δx

from the given points

m = (-7 - -1)/(5 - 6)

= -6/-1

= 6

Considering the points x₁ and y which are 6 and -1

and using the formular

m = (y - y₁)/(x - x₁)

6 = (y - -1)/(x - 6)

y + 1 = 6(x - 6)