Suppose that consumer usage time of computers in the public library is uniformly distributed with a minimum of 20 minutes and a maximum of 80 minutes. what is the standard devia…

Question

asked Mar 3, 2021 165k views

1 Answer

Kyle Redfearn · Answer 1 · 2021-03-10T15:05:42+0000

Answer:

17.32 minutes

Explanation:

The standard deviation for a uniform distribution is:

$\sigma =(b-a)/(\sqrt12)$

If a = 20 minutes and b = 80 minutes, the standard deviation is:

$\sigma =(80-20)/(\sqrt12) \\\sigma=17.32\ minutes$

The standard deviation of the distribution of consumer usage time of computers in the public library is 17.32 minutes.