Question

What is the initial value for g(x) = 3(1/4)^(x-2) - 3

Answer 1

Answer: g(1) = 9

Explanation:

g(x) = 3(1/4)^(x-2) - 3

g(1) = 3(1/4)^(1-2) - 3

g(1) = 3(1/4)^(-1) - 3

g(1) = 3(4) - 3

g(1) = 12 - 3

g(1) = 9