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Solve for absolute value: 3(r+1)+2>-7

1 Answer

11 votes

Answer:


\huge\boxed{\bf\:r > -4 }

Explanation:


3(r+1)+2 > -7

Use the distributive property to solve 3 (r + 1).


3r+3+2 > -7 \\3r + 5 > -7

Now, bring 5 to the right hand side of the inequality .


3r > -7-5 \\3r > -12

Divide both sides of the inequality by 3.


r > (-12)/(3) \\\boxed{\bf\:r > -4 }


\rule{150pt}{2pt}

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User Satvik
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