Question

Two passenger trains traveling in opposite directions meet and pass each other. Each train is 1/12 mi long and is traveling 50 mph. How many seconds after the front cars of the trains meet will their rear cars pass each other?

Answer 1

6 seconds

Explanation:

Total distance between the 2 rear cars =
`\\(1)/(12) + (1)/(12) = (1)/(6)\\\\\\\\\\Relative speed of the trains = 50 + 50 = 100 mphT = (Distance)/(Speed) = (1)/(6) * (1)/(100) = (1)/(600) hours\\T = (1)/(600) hours or (3600)/(600) = 6 seconds`