asked 105k views
1 vote
Find the derivative of
y = arcsin(x)​

asked
User Damianmr
by
8.0k points

2 Answers

6 votes

Answer:

1 /√( 1 - x^2).

Explanation:

y = arcsin x

x = sin y

dx/dy = cos y

dy/dx = 1 / cos y

Now cos y = √( 1 - sin^2 y)

but sin y = x so

cos y = √( 1 - x^2).

So dy/dx = 1 / √( 1 - x^2).

4 votes

Answer:

f'(x)=
\frac{1}{\sqrt{1-x^(2) } }

Explanation:

As khown the derivative of arcsin(x) is;

f'(x)=
\frac{1}{\sqrt{1-x^(2) } }

answered
User JW Lim
by
8.1k points

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