Question

4Ga + 3S2 → 2Ga2S3

1. How many grams of Gallium Sulfide would form if 20.5 moles of Gallium burned?

Answer 1

`m_(Ga_2S_3)=2415.31gGa_2S_3`

Step-by-step explanation:

Hello,

In this case, for the given chemical reaction, we can notice there is a 4:2 molar ratio between the burned moles of gallium and the yielded moles of gallium sulfide, therefore, we compute them as shown below:

`n_(Ga_2S_3)=20.5molGa*(2molGa_2S_3)/(4molGa)=10.25mol Ga_2S_3`

Then, by using the molar mass of gallium sulfide (235.64 g/mol), we directly compute the grams:

`m_(Ga_2S_3)=10.25mol Ga_2S_3*(235.64gGa_2S_3)/(1molGa_2S_3) \\\\m_(Ga_2S_3)=2415.31gGa_2S_3`

Best regards.