Question

Triangle $ABC$ has its vertices $A$, $B$, and $C$ on the sides of a rectangle 4 units by 5 units as shown. What is the area of triangle $ABC$ in square units?

Answer 1

9

Explanation:

Answer 2

10 square units.

Explanation:

It is given that triangle ABC has its vertices A, B, and C on the sides of a rectangle 4 units by 5 units.

Height of triangle = 4 units

Base of triangle = 5 units

We need to find the area of triangle.

Area of triangle
`=(1)/(2)* base * height`

Substitute base = 5 and height = 4 in the above formula.

Area of triangle
`=(1)/(2)* 5* 4`

Area of triangle
`=(20)/(2)`

Area of triangle
`=10`

Therefore, the area of triangle ABC is 10 square units.