Question

n object is placed at 58.2 cm in front of a diverging lens with a focal length of -18.1 cm. What is the magnification

Answer 1

Step-by-step explanation:

object distance u = -58.2 cm .

Focal length f = -18.1 cm .

from lens formula

`(1)/(v) - (1)/(u) =(1)/(f)`

Putting the values in the formula

`(1)/(v) + (1)/(58.2) =- (1)/(18.1)`

`(1)/(v) + .017=-.055`

`(1)/(v)` = - .072

v = -13.80 cm

magnification

`(v)/(u)`

=
`(13.80)/(58.2)`

= .237 .