asked 86.3k views
4 votes
If $N$ is a positive integer and $N^2 = 91,\!204$, what is the value of $N$?

asked
User Supi
by
8.3k points

1 Answer

2 votes

Answer:

302

Explanation:

Given ...


N^2 = 91,\!204

the value of N is found by taking the square root.


N=√(91,\!204)=\boxed{302}

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