Question

.50-kg stone is dropped from rest at a height of 3.75 m. What impulse does gravity impart to this stone from the instant it is dropped until it hits the ground, assuming negligible air resistance

Answer 1

21.41 kg-m/s.

Step-by-step explanation:

Data provided

Height = 3.75 m

Mass of stone = 2.50 kg

The computation of impulse is shown below:-

First we will compute the time using motion's equation which is

`s = ut + (1)/(2) gt^2`

as,

s indicates height

u indicates initial speed

t indicates time

Now, we will use the equation and put the values

`3.75 = 0 + (1)/(2)* 9.8* t^2\\\\t^2 = (3.75* 2)/(9.8)\\\\t= \sqrt{(3.75* 2)/(9.8) }`

t = 0.874 seconds

After computing the time now we will find put the impulse which is

`J = F* t\\\\J = mg* t`

Now we will put the values into the above formula to reach the impulse

`J = 2.50* 9.8* 0.874\\\\`

J = 21.41 kg-m/s.