Question

Mrs. Carlyle bought a bag of peanuts for her children. when Philip Joy Brent and Preston came home from school and they each took some peanuts from the bag. Phillip took 1/3 of peanuts from the bag Joy took 1/4 of the remaining peanuts. Brent 1/2 of the remaining peanuts. Preston took 10 peanuts there 71 peanuts remaining in the bag. how many peanuts were originally in the bag? how many peanuts in each child take?

Answer 1

Total peanut=324

Explanation:

Let the peanut=x

Philip took 1/3 of x

Remaining peanut=x-1/3x

=3x-x/3

=2/3x

Joy took 1/4 of the remaining leaving 3/4

Remaining=(3/4)(2x/3)

=6x/12

=1/2x

Brent took 1/2 of those, leaving 1/2

=(1/2)*(1/2x)

=1/4x

Preston took 10

Remaining

1/4x - 10 = 71

1/4x = 81

x=81÷1/4

=81*4/1

x = 324

Total peanut =324

Philip=1/3x

=1/3*324

=108

Remaining 324-108

=216

Joy=1/4 of 216

=54

Remaining

324-108-54=162

Brent=1/2 of 162

=81

Preston=10

Total taken=Philip+joy+Brent+Preston

=108+54+81+10

=253

Total remaining=Total peanut - total taken

=324-253

=71