Question

Anyone can help me with my math homework please?

Answer 1

Explanation:

hello,

so we know y in terms of t and x in terms of t and we need to find y in terms of x

`x=21t^2<=>√(x)=√(21)*t \ \ as \ \ t>=0 \ \ So\\t=\sqrt{(x)/(21)}`

and then

`y=f(x)=3\sqrt{(x)/(21)}+5=\sqrt{(9x)/(21)}+5=\sqrt{(3x)/(7)}+5`

hope this helps