Question

A 10.0 mL sample of a 2.5 M NaCl solution is diluted to 25.8 mL. What is the new concentration?

Answer 1

`C_2=0.97M`

Step-by-step explanation:

Hello,

In this case, for dilution process, we can notice that the initial moles remain the same once the dilution is completed, therefore, both concentration and volume change considering:

`n_1=n_2\\\\V_1C_1=V_2C_2`

In such a way for the given final volume, the resulting concentration is noticed to be:

`C_2=(V_1C_1)/(V_2) =(10mL*2.5M)/(25.8mL)\\ \\C_2=0.97M`

This is supported by the fact that the higher the volume the lower the concentration.

Best regards.