Question

Simplify: (2 cot(−240°)cos(-1050°)− cot^2(50°)) / (sec^2(40°))

Thanks! (:

Answer 1

\frac{2\cot \left(-240^{\circ \:}\right)\cos \left(-1050^{\circ \:}\right)-\cot ^2\left(50^{\circ \:}\right)}{\sec ^2\left(40^{\circ \:}\right)}

Explanation:

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