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2 votes
spring stretches by 21.0 cm when a 135 N object is attached. What is the weight of a fish that would stretch the spring by 43.9 cm?

1 Answer

3 votes

Answer:

F2 = 282.28N

Step-by-step explanation:

F = force

E = extension

  • F1/E1=F2/E2
  • 135/21 = F2/43.9
  • 6.43 = F2/43.9
  • F2 = 6.43 x 43.9
  • F2 = 282.28N
answered
User Hashim Adel
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