Question

You use 10.0 mL of solution A, 10.0 mL of solution B, and 70.0 mL of water for your first mixture. What is the initial concentration of KIO3

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The initial concentration is
`C_f = 0.0022 \ M`

Step-by-step explanation:

From the question we are told that

The volume of solution A is
`V_i = 10.0 mL`

The concentration of A is
`C_i = 0.0200 \ M`

The volume of solution B is
`V_B = 10.0mL`

The volume of water is
`V_(w ) = 70.0 mL`

Generally the law of dilution is mathematically represented as

`C_i * V_i = C_f * V_f`

Where
`C_f` is the concentration of the mixture

`V_f` is the volume of the mixture which is mathematically evaluated as

`V_f = 10 + 10 + 70`

`V_f = 90mL`

So

`C_f = (C_i * V_i)/( V_f)`

substituting values

`C_f = (0.0200 * 10 )/(90)`

`C_f = 0.0022 \ M`

Note the mixture obtained is
`KIO_3`