Question

To what volume should you dilute 50.0 ml of 12 m hno3 solution to obtain a 0.100 m hno3 solution?

Answer 1

The answer is "6L"

Step-by-step explanation:

Formula:

`\bold{C_1 * V_1 = C_2 * V_2 }\\\\V_2= (C_1* V_1)/(C_2)`

Values:

`\to C_1= 12 \ m\\\to V_1= 50 \ ml\\\to C_2= 0.100 \ m\\\\\\V_2= (12 * 50 )/(0.100)`

`= (12 * 50 )/(0.100)\\\\= (12 * 50 * 1000)/(100)\\\\= (600 * 1000)/(100)\\\\= 600 * 10\\\\=6000 \ ml\\= 6 \ L`