Question

-5y²+2y=-2 Use the quadratic to solve the equation

Answer 1

`x\in\left\{(1+√(11))/(5)\,;\ (1-√(11))/(5)\right\}`

Explanation:

`-5y^2+2y=-2\\\\-5y^2+2y+2=0\\\\a=-5\,,\ \ b=2\,,\ \ c=2\\\\\Delta=2^2-4\cdot(-5)\cdot2=44\quad\implies\quad\sqrt\Delta=2√(11)\\\\x_1=(-2-2√(11))/(2\cdot(-5))=(-2(1+√(11)))/(-2\cdot5)=(1+√(11))/(5)\\\\x_2=(-2+2√(11))/(2\cdot(-5))=(-2(1-√(11)))/(-2\cdot5)=(1-√(11))/(5)`

Answer 2

the answer in the paper

my correction of there ia am error in the my answer