Question

A tennis player tosses a tennis ball straight up and then catches it after 1.91 s at the same height as the point of release. (a) What is the acceleration of the ball while it is in flight? magnitude m/s2 direction ---Select--- (b) What is the velocity of the ball when it reaches its maximum height? magnitude m/s direction (c) Find the initial velocity of the ball. m/s upward (d) Find the maximum height it reaches. m

Answer 1

Step-by-step explanation:

(a) The acceleration is 9.8 m/s² downwards.

(b) At the maximum height, the velocity is 0 m/s.

(c) v = at + v₀

0 m/s = (-9.8 m/s²) (1.91 s) + v₀

v₀ = 18.7 m/s

(d) Δy = vt − ½ at²

Δy = (0 m/s) (1.91 s) − ½ (-9.8 m/s²) (1.91 s)²

Δy = 17.9 m