Register

How do I get the derivative of y=xtanx ?

How do I get the derivative of y=xtanx ?
asked 126k views
2 votes
How do I get the derivative of y=xtanx ?

asked
User Stefan Meyer
by
7.8k points

1 Answer

5 votes

Answer:


(dy)/(dx)\ = tanx + x *sec^(2)x

Explanation:


y=xtanx

Differentiate with respect to x by using product rule .


y=xtanx\\\\(dy)/(dx)\ = tanx * (dx)/(dx)\ + x * (d(tanx\ ))/(dx) \\As\ \ [(d(tanx))/(dx) =(1)/(sec^(2)x ) \ ]\ so\\\\\\\\\


(dy)/(dx)\ = tanx + x * (1)/(cos^(2)x \ ) \\(dy)/(dx)\ = tanx + x *sec^(2)x

answered
User Coffee Maker
by
8.5k points
← Prev Question Next Question →

Related questions

User Yeimy
asked Oct 2, 2020 14.8k views
What are the critical points for xtanx? Derivative of that is = x(sec^2 x) + tanx
Yeimy asked Oct 2, 2020
by Yeimy
7.8k points
1 answer
3 votes
14.8k views
User Ambuj Jauhari
asked Jan 13, 2017 102k views
Summary of curve sketching (calculus 1) - sketch the graph: xtanx, -pi/2 < x < pi/2
Ambuj Jauhari asked Jan 13, 2017
by Ambuj Jauhari
8.0k points
1 answer
5 votes
102k views
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!