asked 46.4k views
0 votes
*LAST QUESTION , PLEASE ANSWER TY* (: Quadrilateral ABCD is inscribed in a circle. If angle A measures (3x – 10)° and angle C measures (2x)°, find x.

*LAST QUESTION , PLEASE ANSWER TY* (: Quadrilateral ABCD is inscribed in a circle-example-1
asked
User Mhasan
by
9.0k points

1 Answer

4 votes


\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Quadrilaterals.

Basically we know that, the sum of opposite angles of a quadrilateral inscribed in a circle is always 180°.

so applying this law here, we get as,

2X + (3X-10) = 180°

=> 5X - 10° = 180°

=> 5X = 190°

=> X = 190°/5

=> X = 38°

thus the angle X= 38°.

answered
User Jawad
by
7.7k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.