Question

Rewrite the equation by completing the square.
x^2 + 2x - 8 = 0

Answer 1

`\boxed{\sf \ \ (x+1)^2-9=0 \ \ }`

Explanation:

hello,

we can notice that

`(x+1)^2=x^2+2x+1`

so

`x^2+2x=(x+1)^2-1`

and then

`x^2+2x-8=0\\<=> (x+1)^2-1-8=0\\\\<=> (x+1)^2=9\\<=> x+1=3 \ or \ x+1=-3\\<=> x=2 \ or \ x=-4\\`

solutions are 2 and -4

hope this helps

Answer 2

the answers are actually 1 and 9.