Question

Can you help me fill in the blanks

Answer 1

Here is the full proof:

AB || DE Given

∠B = ∠D Alternate interior angles theorem

∠A = ∠E ↑

C is the midpoint of BD Given

BC = CD Definition of midpoint

ΔCBA ≅ ΔBDE SAA

AC = CE CPCTC

C is the midpoint of AE Converse of definition of midpoint