asked 80.8k views
6 votes
How many roots does the function have?

f (x) = x^6+ 2x^5 - 2x^4 + 3x^3 + 4x^2 - 5x + 7


2
6
21
7

1 Answer

6 votes

Answer:

21

Explanation:

6+5+4+3+2+1=21 and there you g9

answered
User Shubhamj
by
8.6k points

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