Question

What if a solid cylinder of mass M = 2.50 kg, radius R = 2.18 cm, and length L = 2.7 cm, is rolling down from rest instead? With h = 79.60 m and x = 4.64 m, what is the center of mass velocity when the cylinder reaches the bottom?

Answer 1

The center of mass velocity is
`v = 32.25 \ m/s`

Step-by-step explanation:

From the question we are told that

The mass of the cylinder is
`m = 2.50 \ kg`

The radius is
`r = 2.18 \ cm = 0.0218 \ m`

The length is
`l = 2.7 \ cm = 0.027 \ m`

The height of the plane is h = 79.60 m

and the distance covered is
`d = 4.64 \ m`

The center of mass velocity o the cylinder when it reaches the bottom is mathematically represented as

`v = \sqrt{(4gh)/(3) }`

substituting values

`v = \sqrt{ (4 * 9.8 * 79.60)/(3) }`

`v = 32.25 \ m/s`