Question

Please just a quick question can, can you help me. The length of a rectangle is 8cm longer than its breadth, If the perimeter of the rectangle is 80 cm, find its length and breadth * choose one of the options 1.length = 16cm and breadth = 64cm 2.length = 16cm and breadth = 22cm 3.length = 24cm and breadth = 64cm 4.length = 24cm and breadth = 16cm

Answer 1

the area of rectangle is 384 sq cm, while the length of the rectangle is 24 cm and width of rectangle is 16 cm

Explanation:

Let the breadth of the rectangle is x cm

Thus the length of the rectangle = (x + 8) cm

We know Perimeter = 2 (length + width)

Perimeter = 2 (x + 8 + x)

Perimeter = 2 (2x + 8)

Perimeter = 4x + 16 cm

4x + 16 = 80 cm

4x = 80 - 16

4x = 64

x = 64/4 cm

x = 16 cm

Thus the width of the rectangle is 16 cm

Length of the rectangle x + 8 = 16 + 8 = 24 cm

We know Area of rectangle = length × breadth

Area of rectangle = 24 × 16 = 384 sq cm

Answer 2

Let's call the width x and the length x + 8. Perimeter can be calculated by multiplying the sum of the length and width by 2 so we can write:

2(x + x + 8) = 80

2(2x + 8) = 80

2x + 8 = 40

2x = 32

x = 16

This means that the length is 16 cm and the width is 24 cm.