Find an expression for the height of a parallelogram whose area is represented by 2x^3 − x^2 − 20x + 3 and whose base is represented by (x + 3).

Question

asked May 7, 2021 112k views

2 Answers

Gotopie · Answer 1 · 2021-05-12T02:24:01+0000

Answer:

The height of parallelogram is
2x^2-7x+1

Explanation:

Area of parallelogram =
Base * Height

Area of parallelogram =
2x^3 -x^2 -20x + 3

Base of parallelogram = x+3

So,
2x^3-x^2-20x + 3 = height * (x+3)

$(2x^3- x^2 -20x + 3)/(x+3)= height\\2x^2-7x+1=Height$

Hence The height of parallelogram is
2x^2-7x+1