Question

What are the zeroes of f(x) = y2 - 2x - 3?

Answer 1

x=y^2/2 - 3/2

Explanation:

Answer 2

Explanation:

Product = -3

Sum = -2

Factors = -3 , 1

y² - 2y - 3 = y² + y - 3y - 3

= y( y + 1) - 3(y + 1)

= (y +1) (y - 3)