Question

Hi The point C lies on a straight line AB and CD is a ray . If /ACD = 470 and /DCB = x0, find the value of x. Does anyone know the answer of this question ?

Answer 1

x=133 degrees

Explanation:

The diagram is drawn and attached below.

Now, AB is a straight line.

`\angle ACD+ \angle DCB =180^\circ $ (Linear Postulate)\\47^\circ+x^\circ=180^\circ\\x^\circ=180^\circ-47^\circ\\x^\circ=133^\circ`