Question

2. At the earth’s surface, a projectile is launched straight up at a speed of 10. 0 km/s. To what height will it rise? ignore air resist

Answer 1

5.097 m

Step-by-step explanation:

H = vo t - 1/2 a t^2

= 10t - 1/2 (9.81) t^2 max occurs at -b/2a = 10/9.81=1.0194 sec

sub in this 't' value to get H =5.097 m