Question

A rocket is stopped 34 feet from a satellite when it begins accelerating away from the satellite at a constant rate of 18 feet per second per second. The distance between the rocket and the satellite is given by the polynomial P(t) = 9t2 + 34. Find the distance between the rocket and the satellite 10 seconds after the rocket started moving.

Answer 1

The distance between the rocket and the satellite 10 seconds after the rocket started moving is of 934 feet.

Explanation:

The distance between the rocket and the satellite, in feet, after t seconds, is given by the following equation:

`P(t) = 9t^(2) + 34`

Find the distance between the rocket and the satellite 10 seconds after the rocket started moving.

This is P(10).

`P(t) = 9t^(2) + 34`

`P(10) = 9*(10)^(2) + 34 = 934`

The distance between the rocket and the satellite 10 seconds after the rocket started moving is of 934 feet.