Question

98-x2=0 solve this with the quadratic formula

Answer 1

x∈{-7√2, 7√2}

Explanation:

`98-x^2=0\\\\-x^2+98=0\\\\a=-1\,,\ \ b=0\,,\ \ c=98\\\\x_1=(-0-√(0^2-4\cdot(-1)\cdot98))/(2\cdot(-1))=(-√(4\cdot49\cdot2))/(-2)=(-2\cdot7√(2))/(-2)=7\sqrt2\\\\x_2=(-0+√(0^2-4\cdot(-1)\cdot98))/(2\cdot(-1))=(2\cdot7√(2))/(-2)=-7\sqrt2`