Question

Please simplify will give brainliyest

Answer 1

`\displaystyle\bf\\-√(m^4n^7)=\\\\=-\sqrt{m^(2*2)* n^(3*2+1)}=\\\\=-\sqrt{m^(2*2)* n^(3*2)* n}}=\\\\=-√(\Big(m^2\Big)^2* \Big(n^3\Big)^2* n)}=\\\\=-√(\Big(m^2* n^3\Big)^2* n)}=\\\\=\boxed{\bf-m^2n^3√(n)}`