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A particular population of chickens has a frequency for the dominant allele as 0.70 and a frequency for the recessive allele as 0.30. Which expression is the correct way to calculate the frequency of individuals that are heterozygous?

1 Answer

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Answer:

the frequency of heterozygous = 2 *0.7 * 0.3

Step-by-step explanation:

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User Yun Luo
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