asked 84.9k views
2 votes
The perimeter of the original rectangle is 16 feet. A small rectangle has a length of 6.2 feet and width of 1.8 feet. A larger rectangle has a length of 12.4 feet and width of blank. Not drawn to scale What is the perimeter of the enlarged rectangle? Round to the nearest tenth if necessary. 22.3 feet 31 feet 32 feet 42.7 feet

asked
User Shariff
by
8.1k points

2 Answers

2 votes

Answer: 32

Step-by-step explanation: looking at the length of the bigger rectangle, we can see that it is twice the length of the small one.

Mathematically meaning 12.4 = 2(6.2)

So in the real sense of it, we can conclude that the smaller rectangle was dilated to give the bigger.

So using that, we can see that the width of the larger triangle would be 1.8 * 2 = 3.6 feet

Mathematically, we can calculate the perimeter of a rectangle using the formula;

P =2 (l + b)

Thus P = 2(12.4 + 3.6) = 2(16) = 32 feet

answered
User Cordula
by
7.5k points
5 votes

Answer:

32 feet

Explanation:

looking at the length of the bigger rectangle, we can see that it is twice the length of the small one.

Mathematically meaning 12.4 = 2(6.2)

So in the real sense of it, we can conclude that the smaller rectangle was dilated to give the bigger.

So using that, we can see that the width of the larger triangle would be 1.8 * 2 = 3.6 feet

Mathematically, we can calculate the perimeter of a rectangle using the formula;

P =2 (l + b)

Thus P = 2(12.4 + 3.6) = 2(16) = 32 feet

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