Question

A 0.140-kg baseball is thrown with a velocity of 27.1 m/sIt is struck by the bat with an average force of 5000 N, which results in a velocity of 37.0 m/s in the opposite direction from the original velocity. How long were the bat and ball in contact?

Answer 1

The bat and the ball were in contact for 1.8 x 10⁻³ s

Step-by-step explanation:

Given;

mass of baseball, m = 0.14 kg

initial velocity of the baseball, u = 27.1 m/s

applied force in opposite direction, F = -5000 N

final velocity in opposite direction, v = -37 m/s

Note: The applied force and final velocity are negative because they act in opposite direction to the initial velocity.

impulse received by the body = change in momentum of the body

Ft = Δmv

Ft = mv - mu

Ft = m(v-u)

t = m(v-u) / F

`t = (0.14(-37-27.1))/(-5000) \\\\t = (0.14(-64.1))/(-5000) \\\\t = (-8.974)/(-5000) \\\\t = 0.0018 \ s\\\\t = 1.8*10^(-3) \ s`

Therefore, the bat and the ball were in contact for 1.8 x 10⁻³ s