asked 23.8k views
5 votes
What is the period of the function y= 3/2 cot(3/5x) +5?

A. Pi/5 units

B. 3pi/5 units

C. 2pi/3

D. 5pi/3

asked
User Chabad
by
8.5k points

2 Answers

3 votes

Answer:

D. 5pi/3, period is the distance between the repetition of a function.

Explanation:

answered
User Dread
by
7.9k points
4 votes

Answer:

D; 5pi/3 units

Explanation:

Here, we want to find the period of the function;

y = 3/2 cot (3/5x) + 5

By definition, the period of a function is the interval between two matching points in the function.

Let’s say it is the distance between two peaks, crests, etc on a function.

To find the value of the period. We shall standardize the function.

What this means is that we shall be writing the function in the standard form.

The standard form is as follows;

f(x) = A trig(Bx -C) + D

Where trig refers to the accompanying trigonometric function in question.

Comparing this standard form with our question, we can see that;

A is 3/2

B is 3/5

C is 0

D is 5

Now for cot and tan functions, we shall need to divide pi by the absolute value of B

Thus we have; pi divided by 3/5 which gives 5pi/3 units

answered
User Callombert
by
8.3k points
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