Question

John is standing at the point (-4,-8) and his friend Victor is standing at the point (-4,12). Find the distance between them. A. 20 units

B. -20 units
C. 28 units
D. -28 units

Answer 1

20 units

solution,

Let the points be A and B

A(-4,-8)--->(X1,y1)

B(-4,12)---->(x2,y2)

Now,

`ab = \sqrt{ {(x2 - x1)}^(2) + {(y2 - y1)}^(2) } \\ \: \: \: = \sqrt{ {( - 4 - ( - 4)}^(2) + 12 - ( - 8) ^(2) } \\ \: \: \: \: = \sqrt{ {( - 4 + 4)}^(2) + {(12 + 8)}^(2) } \\ = \: \: \: \: \sqrt{ {(0)}^(2) + {(20)}^(2) } \\ \: \: \: \: = √(0 + 400) \\ \: \: \: = √(400) \\ \: \: = \sqrt{ {(20)}^(2) } \\ \: \: = 20 \: units`

Hope this helps..

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