Answer:
Number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles.
Step-by-step explanation:
The decomposition of potassium trioxochlorate(v) by heat to produce potassium chloride and oxygen gas is given by the balanced chemical equation below;
2KClO3(s) ----> 2KCl(s) + 3O2(g)
From the equation of the reaction, 2 moles of KClO3 produces 3 moles of oxygen gas when it decomposes under standard conditions of temperature and pressure.
The mole ratio of KClO3 to oxygen gas
is 2:3
When 6.9 moles of oxygen gas is produced, (2/3) * 6.9 moles of KClO3 will be required = 4.6 moles of KClO3
Therefore, number of moles of KClO3 required to produce 6.9 moles of oxygen gas is 4.6 moles