Question

A 104.5 mL intravenous (IV) solution contains 5.10 g of glucose (C6H12O6). What is the molarity of this solution? The molar mas of glucose is 180.16 g/mol.

Answer 1

Molarity=0.271M

Step-by-step explanation:

molarity=moles/volume

moles=5.10/180.16

=0.0283 moles

volume=0.1045L

Molarity=0.0283/0.1045

=0.271M