Question

What is the solubility of 2 kilograms of potassium chloride (KCl) dissolved into 750 cm3 of water? A. 0.375g/dm3 B. 1500g/dm3 C. 2.67g/dm3 D. 2666.67g/dm3

Answer 1

D. 2666.67g/dm3

Step-by-step explanation:

Hello,

In this case, we compute the solubility as:

`solubility=(m)/(V)`

Thus, we compute:

`solubility=(2kg)/(750cm^3)*(1000g)/(1kg) *(1000cm^3)/(1dm^3)\\ \\solubility=2666.7(g)/(dm^3)`

Therefore, answer is D. 2666.67g/dm3.

Best regards.