Question

Please help.... this is confusing me:0

Answer 1

See below

Explanation:

IN a right triangle , remember S-O-H-C-A-H-T-O-A <===memorize this!

sin z = O/H = opposite side/hypotenuse = 16/20

cos z = A/H = adjacent / hy[potenuse = 12/20

tan z = O/A = 16/12