Question

3 pts

Question 3
If 41.97 grams of BaCl2 react with unlimited NaOH how many grams of Sodium chloride will be
produced
BaCl2 +2NaOH --> Ba(OH)2 + 2NaCl
type your answer with the correct number of significant figures but NO UNITS.

Answer 1

23.56

Step-by-step explanation:

We know that BaCl₂ is the limiting reactant. We can write the following:

Grams BaCl₂ * Molar Mass of BaCl₂ * Mole ratio * Molar Mass of NaCl

41.97g BaCl₂ * (1 mol BaCl₂ / 208.23g BaCl₂) * (2 mol NaCl / 1 mol BaCl₂) * (58.44g NaCl / 1 mol NaCl) = 23.56g NaCl